shell小游戏猜数字

时间:2014-02-20 03:30 来源:chinaunix.net 作者:chinaunix.net

生成的密码和用户输入可以接受重复数字
所以相对一般规则的猜数字可能难度要大不少
本版本规则：
A--数字对，位置也对
B--排除A的结果后，数字对，但位置不对
开始后，系统化初始化一个4位可重复数字，如“1223”。假设用户第一次输入“1234”，那么系统将提示“2A1B”，前两位数字“12”相同并且位置也相同，为“2A”。后两位数字中，用户输入的“3”与密文中“3”相同，但两者位置不同，则为“1B”，最终结果为“2A1B”。
再假设用户此时输入“1232”，那么结果则为“2A2B”，计算方法与前次一样。

代码如下

#!/bin/bash
clear
echo
echo "###################################################################"
echo "# this is a bash-shell game write by Email:breeze7086@gmail.com #"
echo "# the game called *digits*,and this version have repeated numbers #"
echo "#                           version 1.0                           #"
echo "###################################################################"
echo -e "\n\n"
declare INPUT
declare PASSWORD
declare A
declare B
declare X
declare Y
declare LOOP
#This funtion init the variable PASSWORD that user need to guess
init_password()
{
        PASSWORD=`echo $(($RANDOM%10000))`
        echo $PASSWORD | grep '^[0-9]\{4\}$' >/dev/null 2>&1
        if [ $? != 0 ]
        then
                init_password
        else
                input
        fi
}
#This funtion accept the input from user's keyboard
input()
{
        echo -n "please input a number between 0000-9999:"
        read INPUT
        echo $INPUT | grep '^[0-9]\{4\}$' >/dev/null 2>&1
        if [ $? != 0 ]
        then
                echo "retry a number between 0000-9999 and do not input a char"
                input
        else
                judge
        fi
}
#This funtion is the main funtion
judge()
{
        X=$INPUT
        Y=$PASSWORD
        while [ $INPUT != $PASSWORD ]
        do
                A=0
                B=0
                judge_a
                judge_b
                LOOP=`expr $LOOP + 1`
                echo "****************************"
                echo "*           "$A"A"$B"B           *"
                echo "****************************"
                input
        done
}
#This funtion count the variable A's value
judge_a()
{
                for i in `seq 4`
                do
                        VAR_INPUT=`expr substr "$X" $i 1`
                        for j in `seq 4`
                        do
                                VAR_PASSWORD=`expr substr "$Y" $j 1`
                                if [[ $VAR_INPUT = $VAR_PASSWORD && $VAR_INPUT != "" && $VAR_PASSWORD != "" && $i = $j ]]
                                then
                                        A=`expr $A + 1`
                                        X=`expr substr $X 1 "$[$i-1]"``expr substr $X "$[$i+1]" 4`
                                        Y=`expr substr $Y 1 "$[$i-1]"``expr substr $Y "$[$i+1]" 4`
                                        judge_a
                                fi
                        done
                done
}
#This funtion count the variable B's value
judge_b()
{
                for i in `seq 4`
                do
                        VAR_INPUT=`expr substr "$X" $i 1`
                        for j in `seq 4`
                        do
                                VAR_PASSWORD=`expr substr "$Y" $j 1`
                                if [[ $VAR_INPUT = $VAR_PASSWORD && $VAR_INPUT != "" && $VAR_PASSWORD != "" ]]
                                then
                                        B=`expr $B + 1`
                                        X=`expr substr "$X" 1 "$[$i-1]"``expr substr "$X" "$[$i+1]" 4`
                                        Y=`expr substr "$Y" 1 "$[$j-1]"``expr substr "$Y" "$[$j+1]" 4`
                                        judge_b
                                fi
                        done
                done
}
#This is the begin of script
LOOP=1
init_password
echo "#############################################"
echo "#congratulations!You have tried $LOOP times!    #"
echo "#        The password is $PASSWORD !             #"
echo "#############################################" (责任编辑：IT)

shell小游戏 猜数字

时间:2014-02-20 03:30 来源:chinaunix.net 作者:chinaunix.net

shell小游戏猜数字